-x^2+9.6x=0

Solution for -x^2+9.6x=0 equation:

-x^2+9.6x=0

We add all the numbers together, and all the variables

-1x^2+9.6x=0

a = -1; b = 9.6; c = 0;
Δ = b2-4ac
Δ = 9.62-4·(-1)·0
Δ = 92.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.6)-\sqrt{92.16}}{2*-1}=\frac{-9.6-\sqrt{92.16}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.6)+\sqrt{92.16}}{2*-1}=\frac{-9.6+\sqrt{92.16}}{-2}
$